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As k+2, 4k-6, 3k-2 are in AP
∴ the common difference between them is same
⇒ 4k-6-(k+2) = 4k -6-k-2 = 3k-8 ------------(1)
⇒3k -2-(4k-6) = 3k-2-4k+6 = k+4-----------(2)
from 1 and 2
⇒3k-8 = k+4 
∴ k= 6

Thank you....!!!
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Yours, Jahnavi
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