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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Let us take first number as x Then the second number becomes x + 1 Acc. to question, (x)(x+1) = 3192 x2 + x - 3192 = 0 x2 + 57x - 56x - 3192 = 0 (via factorisation) x ( x + 57 ) - 56 ( x + 57 ) = 3192 (x - 56) ( x + 57)

so the smallest numbers are 56 and -56 since, 56 x 57=3192 -56 x -57 = 3192

Let the numbers be x and x+1 Given that the product of these two numbers = 3192 (x)(x+1) = 3192 ⇒x² + x - 3192 = 0 ⇒x² - 56x +57x - 3129 = 0 ⇒x(x-56) + 57(x-56) = 0 ⇒(x-56) (x+57) = 0 ⇒(x-56) = 0 or (x+57) = 0 ⇒x = 56 or x = -57 ∴The numbers must be x=56 , x+1=56+1=57 ∵56×57= 3129 OR The numbers must be x = -57 , x+1= -57+1= -56 ∵-57×-56=3129