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A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. The heap is to be covered by canvas to protect it from rain. Find the

area of canvas required.


ar.of canvas required = l.s.a of cone
= πrl
=99 m
0 0 0
I=sqrt 10. 5/2+3 =6.05m Ar of canvas req.=I. s.s.a of cone =22/7×5.25×6.05 =99m
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