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At 27'C, H 2 is leaked through a tiny hole into a vessel for 20 minutes.

Another unknown gas at the same T and P as that of H 2 is leaked
through the same hole for 20 minutes. After effusion of the gas, the
mixture exerts a pressure of 6 atm. The H 2 content of the mixture is 0.7
moles. If volume of the container is 3 litres what is the molecular
weight of unknown gas ?



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P V = (n1 + n2) R T

Substituting P = 6 atm,  V = 3 litre, R = univ gas constant, T = 300 K

We get (n1 + n2).

  n1 = H2 content is 0.7 moles.

So you find the other n2 = (n1+n2) - 0.7

0 0 0
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