# Prove that if diagonal of parallelogram are bisecting each other at 90 degree then it is square.

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The Brainliest Answer!

suppose ABCD is the parallelogram named in order, then consider the triangles COD and AOD

CO=OA [diagonals bisect each other]

∠COD=∠AOD= 90°. [given]

OD=OD [common]

∴Triangle COD congruent to Triangle AOD.

⇒ AD=CD [CPCT]

⇒CD=AB

⇒AD=BC

⇒AD=CD=BC=AB

∴All sides are equal.

∴ABCD is a SQUARE.

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