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The Brainliest Answer!
2015-12-21T20:25:27+05:30
We know that in a parallelogram, opposite sides are equal and the diagonals bisect each other. 
suppose ABCD is the parallelogram named in order, then consider the triangles COD and AOD
CO=OA [diagonals bisect each other]
∠COD=∠AOD= 90°. [given]
OD=OD [common]
∴Triangle COD congruent to Triangle AOD.
⇒ AD=CD [CPCT]
⇒CD=AB
⇒AD=BC
⇒AD=CD=BC=AB
∴All sides are equal.
∴ABCD is a SQUARE.

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