**Three things to do :**

1. Finding the respective improvements of each student - A and B (I prefer to do it in percentage)

**2. **Do comparison between the improvement rates of each student.

**3. **The one with higher improvement rate showed more improvement out of the two.

**1. FINDING IMPROVEMENT RATES****A's Improvement:**

---------------------------------------------------

(Fraction)

**IMPROVEMENT: **

After cancellation, in

** the simplest form** -

or

---------------------------------------------------

---------------------------------------------------

(Percentage)

**IMPROVEMENT: **

%

**Simplification **

=

%

**= **%

**= **% /3

**=** %

**= **% it really goes on forever and it is sufficient to just use the number up to 2 or 3 decimal places.

---------------------------------------------------

So, A's overall improvement is

or

or

%

**B's Improvement: **-------------------------------------------

(Fraction)

**IMPROVEMENT: **

After cancellation, in

** the simplest form** -

or

---------------------------------------------------

(Percentage)

**IMPROVEMENT: **

%

**Simplification **

=

%

**= **%

**= **%

**=** %

------------------------------------------------

---------------------------------------------------

(Decimal)

Fraction=

%

Simplification =

-------------------------------------------------

So, B's overall improvement is

or

or

% or

**2. COMPARISON**

(Fraction)

**A's improvement: **

B's improvement:

(Percentage)

**A's improvement: **

%

B's improvement:

%

%

**> **%

**3. RESULT**So, after comparison, we can conclude that B student has shown more improvement than A student.