Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Answer:) Let the radius and height of the cylinder be, 'r' cm and 'h' cm respectively.
Given:) TSA of the cylinder = 462 cm2
∴ 2p r (r + h) = 462 cm2 .. .(1)
Given:) LSA of cylinder = 1/3 × TSA of cylinder...
∴ 2prh =1/3 × 462 = 154 cm2 ... (2)
From (1) and (2), we have
{2pr(r+h}/{2pr} = 462 cm2 / 154 cm2
(r+h) / h = 3
r = 3h-h=2h
r = 2h
From (2), we have
2prh =154 cm2
(2 x22rxr) /(7x2)}
r = 7cm
h = r/2=7/2=3.5cm
∴ Vol of the cylinder = pr2h =22x7x7/3.5=539 cm2.......

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Total surface area = (2π r h + 2 π r²) = 462 cm² curved surface area = 2 π r h = 462/3 = 154 cm ² so, 2π r² = ( 462 - 154) =308 ⇒ r² = 154 /π = 49 ⇒ radius = 7 cm now, 2π r h = 154 cm² ⇒h = 154 /2π r = 3.5 height = 3.5 cm