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2015-12-21T10:53:20+05:30

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Considering, these are three different numbers, i.e. 1089 , 2304, 6084
By prime factorization (dividing with prime factors )
1089 = 3×3×11×11
√1089 = √(3×3×11×11)
           =3×11 =33
2304 = 2×2×2×2×2×2×2×2×3×3
√2304 = √( 2×2×2×2×2×2×2×2×3×3)
           =2×2×2×2×3 =48
6084= 2×2×3×3×13×13
√6084 =√(2×2×3×3×13×13)
           =2×3×13 =78
0
please do it in division method as the user who has asked this question wants the answer in division method
no option for editing now??
ok...i will ask it to be corrected
ok..thanks 
:)
2015-12-21T22:38:50+05:30
Please see the attachment.
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please mark my answer as the best