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A solid cube is cut into 2 cuboids of equal volumes.find the ratio of the total surface area of the given cube and that of one of the cuboids.




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Let the side length of cube = a units
total surface area of cube, S = 6 a²
now, it is cut into 2 cuboids, 
total surface area of one cuboid, s' = (6 a²)/2 + a² 
                                                    =4 a²
ratio , S/s' = (6 a²)/(4a²)
so, S:s' = 3:2
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