Answers

2015-12-23T08:08:10+05:30
AM ( arithmetic mean ) >= HM ( harmonic mean )

considering x^2 & y^2 as elements

AM = (x^2 +y^2)/2 >= HM = 2/( 1/x^2 + 1/y^2 )

=> x^2 + y^2 >= 2/(1/x^2 + 1/y^2 )

=> 1/x^2 + 1/y^2 >= 2/x^2 + y^2

=> 1/x^2 + 1/y^2 >= 2/c^2

Thefore , the minimum value of 1/x^2 + 1/y^2 = 2/c^2
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2015-12-23T14:26:29+05:30
Is 90 ok
ok
ok
ok
so that's ir
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