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area of triangle = (1/2) × base×height
if we take AC as perpendicular then AB will be base.
then area of triangle = (1/2)× 5×12 = 30 cm²
also, by Pythagoras' theorem, 
BC² = AC² +AB²
       =12² + 5² = 169
BC = 13 cm
now, if AD is perpendicular then BC is the base
area of triangle = (1/2)× BC ×AD
⇒30 = (1/2)× 13×AD
AD = 60/13 =4.61 cm
0 0 0
is any wrong in calculation???
sorry my sister written wrong
okey..if you find any error..please do inform me :)
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