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angles

a+b+c+d = 360*

115+x+115+x = 360

2x = 360-115+115=130

x = 130/2

x = 65*

so angle a = angle c = 115*

angle b = angle d = 65*

opp sides are equal

so

ab = dc =5cm

ad=bc=7cm

cd = 5 cm,

ad =7 cm

in a parallelogram as opp sides are equal ad = bc = 7 cm

and ab = dc = 5 cm

and as angles are equal in a ll gm <a = < c = 115 degrees

the sum of all <'s in a ii gm = 360 degrees

so, 360-230=130( 115 + 115 =230 )

230 /2 =65

hence ,< a =115, <c =115 ,<b = 65 and < d =65