Log in to add a comment

Log in to add a comment

No. Of days 365

A leap year has 53 sundays and the other two days

May be (sat, sun)(sun,mon) (mon,tues) (tues,wed)(wed,thur)(thur,fri)(fri,sat)

Total no. Of all possible outcome is 7

Let e b the getting 53 sun in leap year

No. Of favourable outcome is n(e) is 2

No. Of all possible outcome n(s) is 7

P(e)=n(e)/n(s)= 2/7

in a leap year there will be 52 weeks

and 2 extra days.

therefore there will be 52 sundays

compulsarily the remaining 2 days can be

mon. tues.

tues. wed.

wed. thurs.

thurs. fri.

fri. sat.

sat. sun.

sun. mon.

these will be the possibilities .

n(e) = 2 (because in the 7 possibilities 2 contain sundays)

n(s) = 7 (total possibilities.)

P(e) = 2/7

pls. mark as best if it is clear.