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2015-12-27T08:34:48+05:30

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Number of 10 paisa coin = x
number of 25 paisa coin =y
A/q,
x - y = 3 
⇒x = 3 +y
and, 10x + 25y = 310
⇒ 10 ( 3 +y) + 25y = 310
⇒30 +10y + 25y = 310
⇒35 y= 280
⇒y =8 and x = 11
there are 11 coins of 10 paisa and 8 coins of 25 paisa
0
2015-12-28T15:46:05+05:30
Let x be the number of 10 paise coins and y be the number of 25 paise coins.
given,
10x+25y=310                     [3.10=310 paise]
divide the eqn by 5,
we get,
2x+5y=62-------------------(1)
then, x-y=3
multiply the eqn by 2,we get,
2x-2y=6---------------------(2)
(1)-(2)======>7y=56
thus, y=8.
putting y=8 in (1)
2x=62-40
    =22
thus x=11.
ans:there are 11 10 paise coins and 8 25 paise coins
1 5 1