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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

A tent consists of a frustum of a cone, surmounted by a cone. If the diameter of the upper and lower circular ends of the frustum be 14m and 26m

respectively. The height of the frustum be 8m and the slant height of the surmounted conical portion be 12m, find the area of canvas required to make the tent.(Assume that the radii of the upper circular end of the frustum and the base of surmounted conical portion are equal)

now,diameter, d, of cone = 14m...radius,r=7m slant height, l = 12m ∴curved surface area=πrl =π×7×12 =π×84 =264m²

∴area of canvas required = curved surface area of frustum + curved surface area of cone =[852.3+264]m² =1116.3m² ANS:1116.3 m² of canvas is required

mark as brainiliest plz if it helped sry as i haven't given in symbols..for sqrt().....in the above equations..coz they weren't coming when i saves the answer.nd the value of pi,π=22/7