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A person of mass M is equal to 90 kgs standing on a smooth horizontal plane of ice throws a body of mass is equal to 10 kgs horizontally on the same

surface if the distance between the person and body after 10 seconds 10 metres the the kinetic energy of the person in joules is how much


It would be more better if you elaborate it.

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k.e.on the body = 1/2*m*v^2
Now acc. to newton's 3 law every action has equal and opposite reaction
Now if we neglect friction as the floor is smooth
Forceput on the body = m*a =10*1=10N
So,force on the person =m*a
a =1/9=0.111111
v = a*t(when u=0)
v= 0.1111*10
k.e. of person =1/2*90*1.1^2
k.e. = 45*1.21=54.45J
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