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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Since the middle number of the three consecutive numbers is x, the other
two numbers are x -1 and x +1.
According to the given condition, we have x² = [(x +1)² -(x -1)²] +60 x² = (x² +2x +1) -(x² -2x +1) +60 = 4x +60 x² -4x -60 = 0 => (x -10)(x +6) = 0 x = 10 or -6
Since x is a natural number, we get x = 10
Hence the three numbers are 9, 10, 11

Question: Three consecutive natural numbers are such that the square of the middle number exceeds the difference of the squares of the other two numbers by 60.