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Let 2 equal sides be a and b let the otherside be c length of 1 of the equal sides =c-5 perimeter of the triangle =a+b+c=55m =c-5+c-5+c=55m =3c-10=55m =c=55-10/3 =c= 45/3= 15m a =c-5=15-5=10m b=a=10m c=15m

He has done the wrong answer.
let the three sides be a,b and c a+b+c=55m a.t.q., c-5+c-5+c=55 3c-10=55 3c=55+10 3c=65 c=65÷3 c=21.66......... c=22m now,if c=22m then a and b =22-5=17m please mark as brainliest answer and click thanks.