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as we know that when there is a free fall of an object,the decrease in potential energy at any point on its path,appears as an equal amount of increase in its kinetic energy ...because by the law of conservation of energy energy can neither be destroyed nor be created.

mechanical energy=kinetic +potential (mass=10kg,g=10m/s^2,h=5m) potential energy at the top(maximum)=mgh =10X10X5 =500J kinetic energy when it reaches the ground(maximum)=1/2mv^2 =1/2*10*v^2 potential energy=kinetic energy (law of conservation of energy) 500J=500J

therefore,kinetic energy=500J THE SPEED JUST BEFORE IT HITS THE GROUND IS- 1/2*10*V^2=500 V^2=500/5 V=10 THEREFORE V=10

Mass = 10 kg Height = 5 m so, by equation of position velocity relation v² - u² = 2as u = 0 m/s a = g =10 m/s² s = h = 5m so, velocity just before hitting the ground = 10 m/s and the kinetic energy = 1/2 mv² = 500 J