Answers

2016-01-05T18:26:31+05:30
Ar(ABD)=ar(ADC)    [Triangle on the same base and on between same parallel lines]...(1)
ar(ABE)=ar(AED)    [Triangle on the same base and on between same parallel lines] ....2
ar(BOE)=ar(BOA)  [Triangle on the same base and on between same parallel lines] ....3    now     
2 ar(ABD)=ar(ABC) from1
4ar(ABE)=ar(ABC) from2
8ar(BOE)=ar(ABC) from3  So;ar(BOE)=1/8ar(ABC) proved
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