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(x + 1)(x + 4)(x + 2)(x + 3) = 120

( x² + 5x + 4)( x² + 5x + 6) = 120

In this We will take x² +5x =y

so, (y+4)(y+6)=120

y² + 10y + 24 = 120

y² + 10y - 96 = 0

y² - 6y + 16y - 96 = 0

y(y-6)+16(y - 6) =0

(y + 16)(y - 6) = 0

now , y = -16 and y = 6

so, putting the value of y

x² + 5x = 6

x² + 5x - 6 =0

x² + 6x - 1x - 6 = 0

x(x + 6)- 1(x + 6) = 0

(x -1)(x+6) = 0

now, x = -6 and x = 1

so x is equal to 1, -6

now, if we put y = -16 ,then it will be complex

and on putting 1 ans. is 72 and on putting -6 ans. is 120

so, -6 is the answer.

X+1)(x+2)(x+3)(x+4) = 120

x+1+x+2+x+3+x+4=120

4x + 10 =120

x+10 = 120/4

x = 30 - 10 = 20

**so x = 20**

x+1+x+2+x+3+x+4=120

4x + 10 =120

x+10 = 120/4

x = 30 - 10 = 20