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Name the square as A, B, C and D

Draw a line from A to C
Let AB=8cm
Let AC=11cm
Let BC=?

In triangle ABC
AB^2 + BC^2 = AC^2 :


(8cm)^2 + BC ^2 = (11cm)^2
= 64cm^2 + BC ^2 = 121cm^2
= BC^2 = 121cm^2 - 64cm^2
= BC^2 = 57cm^2
= BC = 57cm^2 root
= BC = 7.54 cm
Therefore; Height of the triangle = 7.54cm
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