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A and B can do a piece of a work in 12 days , B and C in 15 days, B and A in 20 days

. How much time will A alone take to finish the work?


1/A' + 1/B' = 1/12
1/B' + 1/C' = 1/15
as A', B', C' here are the number of days and since A is twice the good worker then C therefore he will complete the job in half days. Therefore C' = 2*A'

1/A' - 1/C' = 1/60
1/C' = 1/2A'

Therefore A' = 30 days
B' = 20 days
C' = 60 days

I hope it helps you 

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