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3(log7 - log5) 
= 3(log7/5) [ ∵ logM - logN = log M/N]
= log(7/5)³  [ ∵ Mlog n = log n^M]
Assume that
log(7/5)³ to the base `e` =  x
⇒e^x = (7/5)³
0 0 0
It would be my pleasure if  you told me the solution  for  the question above for the base 10 instead of base e plz .
In return i would thank you on your profile.
reply soon.
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