Answers

2016-01-13T12:06:01+05:30
Area of Δ when coordinates are given is 
given S(-6 , -2)
I(-8 ,-5)
M(-4,-5)
x1 = -6, x2 = -8, x3 = -4
y1 = -2, y2 = -5, y3 = -5
Δ = 1/2[(x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
   = 1/2 { -6[-5 -(-5)] + (-8)[ -5 -(-2)] + (-4)[ -2 -(-5)]}
   = 1/2 { -6(-5+5) +(-8)[-5+2] + (-4)[ -2+5]}
   = 1/2 { -6(0) + (-8)[-3] +(-4)[3]}
   = 1/2 { 0 +(24) + (-12)}
   = 1/2 {24-12}
   = 1/2 { 12 }
   = 12/2 
   = 6 
∴ Area of the Δ = 6 units²
1 5 1
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