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  • JCL
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The quadrilateral you were talking about is Trapezoid/Trapezium

A = \frac{9cm+11cm}{2}10cm\\A= \frac{20cm}{2} 10cm\\A=10cm(10cm)\\A=100cm^2

Click image for proof.
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note: it can't be a rectangle/parallelogram because of the length of the sides ☺
good answer
JCL. . the parallelogram I am talking about in my digram is the ABCF
It is a trapezium
So the formula of finding the area on trapezium in
1/2 *height*[sum of the lengths of the parallel sides]

So to find height use the Pythagoras theorem to get AF(given in my rough digram)

AF = 10.5

So the height is 10.5

Then,put the values

=110.25 cm^2
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