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Let the height of the parallelogram be h and the height of COD be x So the height of AOB will be h-x. Opposite sides are equal So bases if both the triangles is equal. Ar(aob)+ar(cod)=1/2*(h-x)*base + 1/2 * x*base =1/2*base[h-x+x] =1/2*(base* h) Base* height= 40 Area of both triangles is 1/2*40 That is 20
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