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The perimeters of two similar triangles are 30 and 20 respectively. if one side of the first triangle is 12cm determine the corresponding side of the other



GIVEN perimeter of 1st traiangle =30
             perimeter of 2nd triangle=20
             side of first triangle =12cm
∴side of 2 nd triangle =30÷20=12÷x(let x be  corresponding side of 2 nd triangle) 
          ∴ cross multiply you get side of 2 nd triangle=8cm
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