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In the product of 1 to 100 integers, how many zeroes are there in the ending

solution......this answer can be easly given....short trick are the number is divided by 5,5^2,5^3........i.e no. is divided by 5,25,125......
ex.100*99*98..............*1=100! and now(100/5)=20,100/25=4,100/125=0; so total 20+4=24.(note that when u divide just only take integer part)


11 zeroes will be there in the end
0 0 0
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