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In fig. ,ABC is a triangle in which L is the mid piont of AB and N is the mid point of AB and N is a point on AC such that AN=2CN . A line through L,

parallel to BN , meets AC at M . proove that : AM=CN


By mid- point theorem Ml || NB therefore ML = 1/2NB , AM = 1/2 AN , therefore AM=CN
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