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therefore

pq=pr

or, (x-7)^2+(0-6)^2=(x-*-3)^2+(0-4)^2

or, x^2-14x+49+36=x^2+6x+9+16

or, -20x+85=25

or, -20x=-60

or, x=3

therefore, p(3,0)

The Brainliest Answer!

That means, PA = PB

Using the distance between two points formula

⇒

⇒

⇒

⇒ 20x = 60

⇒x = 3

The point on X axis which is equidistant from the points (7,6) and (–3,4) is (3,0)