An engineer standing pn the ground level at certain distance from the tower observed that angle of elevation is 60°. By moving furture distance of 30 m away from his original position he observed that the angle of elevatipn is 30°. Help him to find the height of the tower

2

Answers

2016-01-24T23:08:31+05:30
Height of tower → h = 15√3m
0
2016-01-25T07:19:01+05:30
Tan 30 =AB\BC
1/root3=h/x
x= root3 h
Height of tower is 15root 3
0