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An engineer standing pn the ground level at certain distance from the tower observed that angle of elevation is 60°. By moving furture distance of 30 m

away from his original position he observed that the angle of elevatipn is 30°. Help him to find the height of the tower


Height of tower → h = 15√3m
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Tan 30 =AB\BC
x= root3 h
Height of tower is 15root 3
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