Answers

2016-01-25T20:10:29+05:30
Volume of gulab jamun= volume of cylindrical part + volume of 2 hemispherical ends
                                     = 2
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= 2 x 22/7 x (1.4)^2 x 5 = 61.6 cm^3
61.6 x 30 / 100 = 18.48
so, 81.48 x 45 = 831 (approx.)
2016-01-25T20:20:24+05:30
Volume of agulab jamun= volume of the cylinder + volume of the two hemispherical ends
 r^{2} h+2/3π r^{3} +2/3π r^{3}
 r^{2} (h+4/3r)
r=1.4cm
h=5-2*1.4=2.2cm
therefore volume of of a gulab jamun=
22/7*1.4*1.4(2.2+4/3 * 1.4)
=25.05cu.cm
volume of 45 gulab jamuns = 45* 25.05=1,127.25cu.cm
volume of syrup=30% volume of gulab jamuns
=30/100* 1,127.25=338.17cu.cm
therefore 338.17 cu.cm of syrup is found
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