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AP=9,17,25,....... Let no. of terms be n a=9 d=17-9=8 S=sum of n terms=636 We know; S=n/2[2a+(n-1)d] 636=n/2[2×9+(n-1)8] 636=n/2[18+8n-8] 636×2=n(10+
0 0 0
1 5 1
sum is 636
please note 636 is the sum, 634 is a mistaken.
answer is correct n=12
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