A heater coil of resistance 40ohm carries a current I.if the power of the heater is 1kWh,calculate the magnitude of I.

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Answers

The Brainliest Answer!
2016-01-27T16:55:07+05:30
Power =  current^{2}  × resistance.
1000 w =  I^{2}  × 40   [∵1kw = 1000 w]
 I^{2} = 25
I =  \sqrt{25}

I = 5 ampere.
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