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A heater coil of resistance 40ohm carries a current I.if the power of the heater is 1kWh,calculate the magnitude of I.

I have corrected it.
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The Brainliest Answer!
Power =  current^{2}  × resistance.
1000 w =  I^{2}  × 40   [∵1kw = 1000 w]
 I^{2} = 25
I =  \sqrt{25}

I = 5 ampere.
1 5 1
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