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Draw the figure according to the question. Join PQ. Triangle OPQ is an isosceles triangle. OP and OQ being the radius. Angle OPQ =Angle OQP. Let them be x degrees. Angle TPO= angle TQO =90 degrees Angle TPQ=angle TQP=90-x In triangle TPQ Angle PTQ=180-(90-x+90-x) (by angle sum property ) On solving angle PTQ=2x=2 angle OPQ
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