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On a certain sum of money,invested at the rate of 10 percent per annum compounded annually,the interest for the first year plus the interest for the third

year is 2652.find the sum.



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Let the sum be P
As , A = P(1 +R/100)^t
⇒A = P(1+10/100)
Interest = P/10
now, for 3rd year interest, the amount at the end of 2nd year will be sum.
A = P(1 +10/100)^2
now amount for 3rd year will be
A = (121P/100)(1 +10/100)
interest = 331P/1000
P/10 + 331P/1000 = 2652
⇒431P/1000 = 2652
⇒P ≈ Rs 6153
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