# The escape velocity on earth is 11.2 km / s what will be its value on a planet having double the radius and eight times the mass of earth

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Now after comparing with the planet given M'=8M ,R'=2R

therefore new v=(2GM'/R')∧1/2

v = (2G*8M/2R)∧1/2=(2GM*4/R)∧1/2 = 2(2GM/R)∧1/2 = 2ve (from above) = 11.2 *2 =22.4