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Formula is {n(n-3)}/2
where n=no. of sides of the polygon.

so according to question:
solving this equation we get n=9

hence no. of sides of the polygon=9
0 0 0
In a  polygon no of daignols equal to C(n,2) -n where n is no of sides
therefore 27 = C(n,2)
 n_{C}  _{2}= 27
n(n-1)/2  -n =27
n∧2 -3n -54 =0
from above we get two values of n -6 and 9
no of sides cant we negative so 9 is the answer.
or you can simply solve by
n(n-3)/2 = no of daigonals
0 0 0
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