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2016-02-02T21:29:28+05:30

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At height 40 m, the ball have potential energy,
PE = mgh = 5×10×40 = 2000 J
KE =0
Total energy, TE = PE +KE = 2000 J
At half way down PE = mgh/2 = 1000 J
Total energy is always constant
TE =PE + KE
KE = 2000 - 1000 = 1000 J
One can find velocity at this position by applying (1/2 )×mv² = 1000 J
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