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Out of 200 bulbs in a box, 12 bulbs are defective. One bulb is taken out at

random from the box. What is the probability that the drawn bulb is not defective?



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Total nos. of bulbs=200
total nos. of defective bulbs=12
so,total no. of non defective bulbs=200-12=188 bulbs

hence ,probability of drawing a non defective bulb=(nos. of non-defective bulbs)/(total nos. of bulbs)

0 0 0
thank you so much Faisal07 yes 47/50
most welcome :)
P(not defective)=188÷200=0.94
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