Answers

  • qais
  • Content Quality
2016-02-03T11:38:40+05:30
Let the digits are x and y
number will be 10x +y
A/q
x = 3y
now interchanging it, and adding
(10y +x) + (10x +y ) = 44
⇒ 11x + 11y = 44
⇒x +y = 4
⇒3y +y = 4
⇒4y = 4
⇒y = 1
so, x = 3
now number = 10x +y = 10×3 +1 = 31
hence the original number will be 31
also if we take y = 3x
x= 1 and y = 3
then number = 10x +y = 10×1 +3 = 13
then the number will be 13

0
how this last original number takes place as 31
now see..i hope now you'll understand :)