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85 kg of a mixture contains milk and water in the ratio of 27 : 7. How much more water is to be added to get a new mixture containing milk and water in the

Milk : water = 27:7 85kg = 27x + 7x 85 = 34x x = 85/34 x = 2.5 milk = 27x = 27*2.5 =67.5kg water = 7x = 7*2.5 = 17.5kg now x = 2.5 kg 2x = 5 kg add 2x to water 7x + 2x = 9x now the ratio of milk and water is 27:9 = 3:1 so 5 kg of water is required

Milk:water=27:7 total ratio=27+7=34 milk in 85kg of the mixture=27*85/34 =>27*2.5 =>67.5 .'. weight of water in 85kg of the mixture=85-67.5 =>17.5 .'. new ratio=3:1 x=weight of water to be added to get the mixture ratio as 3:1 .'.67.5:17.5+x::3:1 cross multiplying 67.5*1=(17.5+x)*3 67.5=52.5+3x 67.5-52.5=3x 15=3x 5=x .'. 5kg of water must be added to make milk:water ratio=3:1