Answers

2016-02-03T22:13:44+05:30
Let the no.s be x.x+2,x+4
x+x+2+x+4=57
3x+6=57
3x=57-6
3x=51
x=17
the nos are 17,19 and 21
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2016-02-03T22:19:34+05:30
Let the three consecutive odd numbers be y,y+2 and y+4
Now given sum is equal to 57
ie;y+(y+2)+(y+4)=57
ie;y+y+2+y+4=57
ie;3y+6=57
ie;3y=57-6
        =51
Therefore y=51/3
                   =17
Therefore the three consecutive numbers are y=17
                                                                           y+2=17+2=19
                                                                           y+4=17+4=21
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