# Find the value of k for which the quadratic equation (k-2)x^2 + 2(2k-3)x +(5k-6) = 0 has equal roots

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The Brainliest Answer!

=> (4k-6)²-4(k-2)(5k-6)=0

= (16k²+36-48k)-4(5k²-16k+12) =0

= 16k²+36-48k-20k²-64k-48=0

= -4k²+16k-3=0

i.e., k²-4k+3=0

(k-1) (k-3) =0

k = 1,3