# In a house 2 bulbs of 50 w each are used for 5 hours a day and two 70 w each fans are used 10 hours a day . calculate the units of electricity consumed in a month of 30 days

2
Log in to add a comment

Log in to add a comment

power of both the bulbs=2*0.05=0.1 KW

units used by the bulbs in a day=0.1*5=0.5 units

power of each fan=70W=0.07KW

power consumed by both fans=0.07*2=0.14

units used by the fans in a day=0.14*10=1.4 units

total units consumed in a day=0.5+1.4=1.9 units

units of energy consumed in a month of 30 days=30*1.9=57 units

ans. therefore 57 units of electricity is consumed in a month in the house

Energy of bulbs in 30 days = 2×50×5×30 = 15000 Wh = 15000 kJ

Energy of fans in 30 days = 2×70×10×30 = 42000 Wh = 42000 kJ

Or 57 unit of energy .

I hope the answer is correct .

Please mark as the best if you liked it!

Thank you