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## Answers

lets proceed if a,b,c,d,e are in AP then

(b-a)=(c-b)=(d-c)=(e-d) lets say = t

now b-a = e-d we get a+e = b+d now put this value in given eqn

a+e -4b +6c -4d = b+d -4b -4d +6c

eqn becomes

-3b -3d +6c

now rearrange it

(c-b) + (c-b) + (c-b) +(c-d)+(c-d)+(c-d)

t+t+t -t -t -t =0 (since c-b =t and d-c=t therefore c-d = -t)

Mark it as brainliest answer