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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Suppose edge of cube= 10cm if we increase it by 20%=12cm #surface area with out increasing edge=6l^2 6 x 10^2=600cm^2 #surface area with increased edge=6l^2 6 x 12^2= 864cm^2 #increase in surface area = 864-600=264 ~ %age increased in surface area = 264/600 x 100=44% plz mark d Best...

Hi! Let the edge of the cube be a Then the Surface Area(S.A) = 6 × a² After increasing the side or the edge of the cube the side will be = a + 20% a = 120 a/100 = (12/10) a Now the new Surface Area ( S.A *) = 6 × (12/10 × l )² Increase in the surface area ( i ) = S.A* - S.A = a²(216 - 150 )/25 =66/25a² Percentage increase(%) = (increase in the surface area) / (Original surface area) × 100% increase = (66/25 a²) / 6 a² ×100% incre = 66/( 25×6) ×100% increase % = 11/25 × 100 % Percentage increase is = 44 % Ans. I hope the answer is correct . Please mark as the brainliest if you are satisfied! Thank you.