Free help with homework

Why join Brainly?

  • ask questions about your assignment
  • get answers with explanations
  • find similar questions


Let the chord be AB and the  centre of the circle is O and the point where the perpendicular from O to the chord=C
OC=5m and OA= 10cm
in ΔOAC,∠C=90degrees
∴By pythagoras theorem,
 OA^{2}=  OC^{2}  +AC^{2}
 AC^{2}=  OA^{2} - OC^{2}
 AC^{2} = 10^{2} - 5^{2} =100-25=75
since the perpendicular from the centre divides the chord into two equal parts=2*5√3=10√3cm
1 1 1
The Brainliest Answer!
Here is the solution , mark best answer please
2 5 2
The Brain
  • The Brain
  • Helper
Not sure about the answer?
Learn more with Brainly!
Having trouble with your homework?
Get free help!
  • 80% of questions are answered in under 10 minutes
  • Answers come with explanations, so that you can learn
  • Answer quality is ensured by our experts