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2016-02-06T16:50:55+05:30

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Let 'a' be the side of the first cube and 'b' be the side of the second one
 a^{3} / b^{3} =27/125
a/b=∛27/∛125
a/b=3/5
the ratios of their surface areas =6a^{2}/6b^{2}
=6*3*3/6*5*5
=9:25
Ans.. therefore the ratio of their surface areas = 9:25
1 5 1
2016-02-09T16:45:18+05:30
Therefore ratio of surface areas of two cubes
= area of frst cube / area of second cube
= (3* x^(2/3) ) / (5* x^(2/3))
= 3:5
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